What is the domain of f(x)=sqrt(x-1)+6 ?

The domain of f(x)=sqrt(x-1)+6 is x>= 1

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domain of f(x)=sqrt(x-1)+6

domain

f (x) = x - 1 + 6

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

6 x + 4 y = 3

f (x) = 2 x^{3} + 24 x^{2} + 72 x

2 x + 2

(x - 4)^{2}

- 2 x + 4

What is the domain of f(x)=sqrt(x-1)+6 ?
The domain of f(x)=sqrt(x-1)+6 is x>= 1