What is the inflection f(x)=2x^3-3x^2-8x+1 ?

The inflection f(x)=2x^3-3x^2-8x+1 is (1/2 ,-7/2)

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inflection f(x)=2x^3-3x^2-8x+1

inflection points

f (x) = 2 x^{3} - 3 x^{2} - 8 x + 1

(\frac{1}{2}, - \frac{7}{2})

Solution steps

f^{''} (x) = 12 x - 6

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{3} - 3 x^{2} - 8 x + 1 : - \frac{7}{2}

(\frac{1}{2}, - \frac{7}{2})

- (x + 3)^{2} + 4

\frac{36 - x ^{2}}{x + 1}

0

f (x) = 4 + 3 x

What is the inflection f(x)=2x^3-3x^2-8x+1 ?
The inflection f(x)=2x^3-3x^2-8x+1 is (1/2 ,-7/2)