frequenz f(x)= 1/4 cos(2x)+5

Lösung

frequenz

f (x) = \frac{1}{4} cos (2 x) + 5

\frac{1}{π}

Dezimale

0.31830 \dots

Schritte zur Lösung

f (x) = \frac{1}{4} cos (2 x) + 5

g (B x - C) = cos (2 x), B = 2

\frac{B}{2 π} = \frac{2}{2 π}

\frac{1}{π}

f (x) = 1 - x^{2}

in v erse f (x) = (x + 7)^{\frac{1}{2}}

in t erce pt s f (x) = e^{x}

in v erse lo g_{2} (2 x)

s l o p e in t erce pt 17 x + y = - 9