What is the domain of (sqrt(x-1))/(2x^2-15x+25) ?

The domain of (sqrt(x-1))/(2x^2-15x+25) is 1 5

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domain of (sqrt(x-1))/(2x^2-15x+25)

domain

\frac{x - 1}{2 x ^{2} - 15 x + 25}

1 \leq x < \frac{5}{2} or \frac{5}{2} < x < 5 or x > 5

Interval Notation

[1, \frac{5}{2}) \cup (\frac{5}{2}, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 5, x = \frac{5}{2}

Combine real regions and undefined points for final function domain

1 \leq x < \frac{5}{2} or \frac{5}{2} < x < 5 or x > 5

f (x) = \frac{1}{x ^{2} + 5 x - 14}

f (x) = 7 + (10 + x)^{\frac{1}{2}}

2 sin (π x + 5) - 4

f (x) = 3 x - 6 y = - 12

f (x) = x + 2 + 2

What is the domain of (sqrt(x-1))/(2x^2-15x+25) ?
The domain of (sqrt(x-1))/(2x^2-15x+25) is 1<= x< 5/2 \lor 5/2 <x<5\lor x>5