monotone (x-5)/(x^2-9)

Lösung

monotone intervalle

\frac{x - 5}{x ^{2} - 9}

Absteigend : - \infty < x < - 3, Absteigend : - 3 < x < 1, Ansteigend : 1 < x < 3, Ansteigend : 3 < x < 9, Absteigend : 9 < x < \infty

Schritte zur Lösung

f^{'} (x) = \frac{- x ^{2} + 10 x - 9}{( x ^{2} - 9 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - 3,

Absteigend

: - 3 < x < 1,

Ansteigend

: 1 < x < 3,

Ansteigend

: 3 < x < 9,

Absteigend

: 9 < x < \infty

Absteigend : - \infty < x < - 3, Absteigend : - 3 < x < 1, Ansteigend : 1 < x < 3, Ansteigend : 3 < x < 9, Absteigend : 9 < x < \infty

am pl i t u d e 4 sin (x)

d o main f (x) = - (x - 3)^{2} + 5

s l o p e in t erce pt x + 5 y = 10

in v erse f (x) = \frac{1}{3 x} - 3

in t erce pt s y = x^{2} - 100