定义域 f(x)=(sqrt(5-x))-(sqrt(x^2-4))

解答

定义域

f (x) = (5 - x) - (x^{2} - 4)

x \leq - 2 or 2 \leq x \leq 5

间隔符号

(- \infty, - 2] \cup [2, 5]

求解步骤

对于根式找到非负值:

x \leq - 2 or 2 \leq x \leq 5

函数定义域

x \leq - 2 or 2 \leq x \leq 5

d o main f (x) = \frac{6 x}{6}

d o main f (x) = \frac{1}{2} x - \frac{9}{2}

r an g e 2 + 3 + 2 x - x^{2}

p er i o d i c i t y f (x) = - cos (\frac{2 x}{5})

in v erse f (x) = (x - 7)^{2} + 8