What is the domain of f(x)=(x-1)/(2x-1) ?

The domain of f(x)=(x-1)/(2x-1) is x 1/2

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domain of f(x)=(x-1)/(2x-1)

domain

f (x) = \frac{x - 1}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

f (x) = (x + 3)^{2}

f (x) = \frac{x}{x + 1}

f (x) = 3 x^{4} - 8 x^{3} + 8

f (x) = x^{2} - 6 x + 4

f (x) = \frac{x + 4}{5 - 3 x}

What is the domain of f(x)=(x-1)/(2x-1) ?
The domain of f(x)=(x-1)/(2x-1) is x< 1/2 \lor x> 1/2