What is the f(x)=(-18x^2-6x+12)/(3x^3+9x-1) ?

The f(x)=(-18x^2-6x+12)/(3x^3+9x-1) is

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f(x)=(-18x^2-6x+12)/(3x^3+9x-1)

f (x) = \frac{- 18 x ^{2} - 6 x + 12}{3 x ^{3} + 9 x - 1}

Domain : x < 0.11065 \dots or x > 0.11065 \dots

Range : - 1.75659 \dots \leq f (x) < 1.67152 E 16

X Intercepts : (- 1, 0), (\frac{2}{3}, 0), Y Intercepts : (0, - 12)

Asymptotes : Vertical x = 0.11065 \dots, Horizontal y = 0

Extreme Points : Maximum (- 2.70319 \dots, 1.22135 \dots), Minimum (1.96066 \dots, - 1.75659 \dots)

Interval Notation

Domain : (- \infty, 0.11065 \dots) \cup (0.11065 \dots, \infty)

Range : [- 1.75659 \dots, 1.67152 E 16)

Solution steps

Domain of

\frac{- 18 x ^{2} - 6 x + 12}{3 x ^{3} + 9 x - 1} : x < 0.11065 \dots or x > 0.11065 \dots

Range of

\frac{- 18 x ^{2} - 6 x + 12}{3 x ^{3} + 9 x - 1} : - 1.75659 \dots \leq f (x) < 1.67152 E 16

Axis interception points of

\frac{- 18 x ^{2} - 6 x + 12}{3 x ^{3} + 9 x - 1} :

X Intercepts

: (- 1, 0), (\frac{2}{3}, 0),

Y Intercepts

: (0, - 12)

Asymptotes of

\frac{- 18 x ^{2} - 6 x + 12}{3 x ^{3} + 9 x - 1} :

Vertical

: x = 0.11065 \dots,

Horizontal

: y = 0

Extreme Points of

\frac{- 18 x ^{2} - 6 x + 12}{3 x ^{3} + 9 x - 1} :

Maximum

(- 2.70319 \dots, 1.22135 \dots),

Minimum

(1.96066 \dots, - 1.75659 \dots)

f (x) = x^{4} - x^{3} - 30 x^{2}

f (x) = \frac{10 - 2 x}{5}

y = 3 (x - 2)^{2} + 5

f (n) = \frac{1}{2 n + 1}

f (x) = x^{2} - 2 ln (x)

What is the f(x)=(-18x^2-6x+12)/(3x^3+9x-1) ?
The f(x)=(-18x^2-6x+12)/(3x^3+9x-1) is