f(t)=sqrt(1+4t^2+9t^4)

Lösung

f (t) = 1 + 4 t^{2} + 9 t^{4}

Parity : Gerade

Inverse : \frac{- 2 + 9 t ^{2} - 5}{3}, - \frac{- 2 + 9 t ^{2} - 5}{3}, - \frac{9 t ^{2} - 5 + 2}{9}, - - \frac{9 t ^{2} - 5 + 2}{9}

Schritte zur Lösung

Parity of

1 + 4 t^{2} + 9 t^{4} :

Gerade

Umkehrung von

1 + 4 t^{2} + 9 t^{4} : \frac{- 2 + 9 t ^{2} - 5}{3}, - \frac{- 2 + 9 t ^{2} - 5}{3}, - \frac{9 t ^{2} - 5 + 2}{9}, - - \frac{9 t ^{2} - 5 + 2}{9}

f (x) = 7 + x

f (x) = 2^{x - 3} + 2

f (x) = 8 x

f (x) = (x - 4)^{2} + 4

f (x) = x^{4} + 4