周期性 tan((pix)/4+(3pi)/4)

解答

周期性

tan (\frac{π x}{4} + \frac{3 π}{4})

4

求解步骤

周期

t an (b x + c) + d = \frac{tan ( x ) 的周期}{∣ b ∣}

tan (x)

的周期是

π

= \frac{π}{\frac{π}{4}}

化简

= 4

d o main 3 (x + 5) + 4

r an g e f (x) = \frac{x}{x + 1}

r an g e f (x) = 2 x + 2

in f l ec t i o n 9 x^{2} - x^{3} - 3

in v erse y = 2 x - 4