inflection f(x)=3x^4-6x^2+2/3

Lösung

wendepunkte

f (x) = 3 x^{4} - 6 x^{2} + \frac{2}{3}

(- \frac{1}{3}, - 1), (\frac{1}{3}, - 1)

Schritte zur Lösung

f^{''} (x) = 36 x^{2} - 12

Intervalle finden:

Konkav steigend

: - \infty < x < - \frac{1}{3},

Konkav fallend

: - \frac{1}{3} < x < \frac{1}{3},

Konkav steigend

: \frac{1}{3} < x < \infty

Stecke

x = - \frac{1}{3}

3 x^{4} - 6 x^{2} + \frac{2}{3} : - 1

(- \frac{1}{3}, - 1)

Stecke

x = \frac{1}{3}

3 x^{4} - 6 x^{2} + \frac{2}{3} : - 1

(\frac{1}{3}, - 1)

(- \frac{1}{3}, - 1), (\frac{1}{3}, - 1)

a sy m pt o t es f (x) = \frac{( 2 + x )}{( x + 5 ) ( x + 7 )}

d o main f (x) = \frac{2 - x}{x ^{2} - 2 x}

r an g e x (x + 11) (x - 6)

in v erse f (x) = 7 x - 5

in t erce pt s y = - 2 x + 7