mittelpunkt (5 1/2 ,-3 1/4),(2 1/4 ,-1 3/4)

Lösung

mittelpunkt

(5 \frac{1}{2}, - 3 \frac{1}{4}), (2 \frac{1}{4}, - 1 \frac{3}{4})

(\frac{3}{2}, - \frac{3}{4})

Schritte zur Lösung

Mittelpunkt von

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (5 \frac{1}{2}, - 3 \frac{1}{4}), (x_{2}, y_{2}) = (2 \frac{1}{4}, - 1 \frac{3}{4})

= (\frac{2 \cdot \frac{1}{4} + 5 \cdot \frac{1}{2}}{2}, \frac{- 1 \cdot \frac{3}{4} - 3 \cdot \frac{1}{4}}{2})

Fasse zusammen

= (\frac{3}{2}, - \frac{3}{4})

d o main f (x) = 2 x - 12

d o main f (x) = 3 x^{2} + 6 x

p a r i t y f (x) = arctan (\frac{x - 1}{x + 1})

in v erse \frac{8 x + 9}{x + 8}

in t erce pt s f (x) = x^{2} - 4 x + 1