d/(dt)(4+2cos((pit)/3))

解答

\frac{d}{d t} (4 + 2 cos (\frac{π t}{3}))

- \frac{2 π}{3} sin (\frac{π t}{3})

求解步骤

\frac{d}{d t} (4 + 2 cos (\frac{π t}{3}))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4) + \frac{d}{d t} (2 cos (\frac{π t}{3}))

\frac{d}{d t} (4) = 0

\frac{d}{d t} (2 cos (\frac{π t}{3})) = - \frac{2 π}{3} sin (\frac{π t}{3})

= 0 - \frac{2 π}{3} sin (\frac{π t}{3})

化简

= - \frac{2 π}{3} sin (\frac{π t}{3})

y = 3^{4 - x} + 1

f (x) = \frac{sin ( 3 x )}{2 x}

f (a) = a^{\frac{5}{7}}

y = e^{s i n h (x)}

f (x) = csc (2 x) - 1