What is the inverse of f(x)=2(x+4)^2-5 ?

The inverse of f(x)=2(x+4)^2-5 is sqrt((x+5)/2)-4,-sqrt((x+5)/2)-4

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inverse of f(x)=2(x+4)^2-5

inverse

f (x) = 2 (x + 4)^{2} - 5

\frac{x + 5}{2} - 4, - \frac{x + 5}{2} - 4

Solution steps

y = 2 (x + 4)^{2} - 5

Replace

x

with

y

x = 2 (y + 4)^{2} - 5

Solve for

y, x = 2 (y + 4)^{2} - 5

\frac{x + 5}{2} - 4, - \frac{x + 5}{2} - 4

f (x) = - 5 x^{2} + 2

f (x) = - x^{2} - 8 x - 8

f (x) = 5 x - 20

sin (\frac{3}{2})

f (x) = 2 - x + 1

What is the inverse of f(x)=2(x+4)^2-5 ?
The inverse of f(x)=2(x+4)^2-5 is sqrt((x+5)/2)-4,-sqrt((x+5)/2)-4