What is the inverse of y=3(x-2)^2+4 ?

The inverse of y=3(x-2)^2+4 is sqrt((x-4)/3)+2,-sqrt((x-4)/3)+2

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inverse of y=3(x-2)^2+4

inverse

y = 3 (x - 2)^{2} + 4

\frac{x - 4}{3} + 2, - \frac{x - 4}{3} + 2

Solution steps

y = 3 (x - 2)^{2} + 4

Replace

x

with

y

x = 3 (y - 2)^{2} + 4

Solve for

y, x = 3 (y - 2)^{2} + 4

\frac{x - 4}{3} + 2, - \frac{x - 4}{3} + 2

y = 1.8 x + 32

f (x) = 3 (x + 4) - 5

f (x) = (\frac{x ^{\frac{1}{7}}}{7})^{3} - 9

f (x) = \frac{2}{3 x}

f (x) = \frac{9 x - 1}{x + 4}

What is the inverse of y=3(x-2)^2+4 ?
The inverse of y=3(x-2)^2+4 is sqrt((x-4)/3)+2,-sqrt((x-4)/3)+2