What is the domain of f(x)=sqrt(9-2/x) ?

The domain of f(x)=sqrt(9-2/x) is x = 2/9

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domain of f(x)=sqrt(9-2/x)

domain

f (x) = 9 - \frac{2}{x}

x < 0 or x \geq \frac{2}{9}

Interval Notation

(- \infty, 0) \cup [\frac{2}{9}, \infty)

Solution steps

Find non-negative values for radicals:

x < 0 or x \geq \frac{2}{9}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x < 0 or x \geq \frac{2}{9}

6 x - 12

\frac{4}{x} - 5

f (x) = ∣ x ∣ + 3 x + 1

\frac{5 x + 3}{2 x - 1}

f (x) = 6 x - x^{3}

What is the domain of f(x)=sqrt(9-2/x) ?
The domain of f(x)=sqrt(9-2/x) is x<0\lor x>= 2/9