inflection-3x^4+16x^3-18x^2

Lösung

wendepunkte

- 3 x^{4} + 16 x^{3} - 18 x^{2}

(\frac{4 - 7}{3}, \frac{1391 - 512 7}{27} - 2 (23 - 87)), (\frac{4 + 7}{3}, \frac{1391 + 512 7}{27} - 2 (23 + 87))

Schritte zur Lösung

f^{''} (x) = - 36 x^{2} + 96 x - 36

Intervalle finden:

Konkav fallend

: - \infty < x < \frac{- 7 + 4}{3},

Konkav steigend

: \frac{- 7 + 4}{3} < x < \frac{7 + 4}{3},

Konkav fallend

: \frac{7 + 4}{3} < x < \infty

Stecke

x = \frac{4 - 7}{3}

- 3 x^{4} + 16 x^{3} - 18 x^{2} : \frac{1391 - 512 7}{27} - 2 (23 - 87)

(\frac{4 - 7}{3}, \frac{1391 - 512 7}{27} - 2 (23 - 87))

Stecke

x = \frac{4 + 7}{3}

- 3 x^{4} + 16 x^{3} - 18 x^{2} : \frac{1391 + 512 7}{27} - 2 (23 + 87)

(\frac{4 + 7}{3}, \frac{1391 + 512 7}{27} - 2 (23 + 87))

(\frac{4 - 7}{3}, \frac{1391 - 512 7}{27} - 2 (23 - 87)), (\frac{4 + 7}{3}, \frac{1391 + 512 7}{27} - 2 (23 + 87))

a sy m pt o t es y = 3 tan (9 x - 7) + 3

in t erce pt s ln ∣ x - 3 ∣

r an g e f (x) = - 2 x + 2 - 3

mi d p o in t (3, - 3), (- 9, 2)

cr i t i c a l x^{8} (x - 1)^{7}