变换 1200+500sin(0.3t)

解答

变换

1200 + 500 sin (0.3 t)

相位 : 0, 垂直 : 1200

求解步骤

f (x) = 1200 + 500 sin (0.3 t)

g (B x - C) = sin (0.3 t), B = 0.3, C = 0, D = 1200

因此，相位变换

\frac{C}{B}

为

\frac{0}{0.3}

0

垂直变换

D

为

1200

1200

a sy m pt o t es f (x) = x^{2} - 1

d o main \frac{1}{x ^{2} - 4}

in v erse f (x) = \frac{x ^{3}}{8} - 3

d o main f (x) = \frac{x - 3}{x ^{2} - 1}

e x t re m e (x^{2} - 9)^{6}