振幅 3cos(x-pi)

解答

振幅

3 cos (x - π)

3

求解步骤

f (x) = 3 cos (x - π), A = 3

因此，振幅 |A| 为

3

3

d o main sin (7 x), 0 \leq x \leq 2 π

in t erce pt s f (x) = 5 (x + 8) - 4

r an g e - x^{2} + 10 x

d o main f (x) = \frac{6 x - 2}{x ^{2} - 36}

e x t re m e f (x) = \frac{x ^{3}}{( x ^{2} - 3 )}