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Popular >

extreme f(x)=(x^2)/(x^2-5)

Solution

extreme points

f (x) = \frac{x ^{2}}{x ^{2} - 5}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{10 x}{( x ^{2} - 5 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} - 5} : 0

Maximum (0, 0)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2)/(x^2-5) ?
The extreme f(x)=(x^2)/(x^2-5) is Maximum(0,0)