extreme 2x^3-3x^2-36x+24

Lösung

extrempunkte

2 x^{3} - 3 x^{2} - 36 x + 24

Maximum (- 2, 68), Minimum (3, - 57)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 6 x - 36

Intervalle finden:

Ansteigend

: - \infty < x < - 2,

Absteigend

: - 2 < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = - 2

2 x^{3} - 3 x^{2} - 36 x + 24 : 68

Maximum (- 2, 68)

Stecke

x = 3

2 x^{3} - 3 x^{2} - 36 x + 24 : - 57

Minimum (3, - 57)

Maximum (- 2, 68), Minimum (3, - 57)

e x t re m e f (x) = \frac{x ^{2}}{x ^{2} + 2}

e x t re m e f (x) = \frac{x ^{2} - 10 x + 21}{2 x - 15}

e x t re m e f (x) = - (x^{2} + 2) (x - 2)

e x t re m e f (x) = x + y + 1

e x t re m e f (x) = x^{3} + \frac{1}{2} x^{2} - 4 x + 2, - 9 \leq x \leq 0