What is the critical f(x)=|x+3|-1 ?

The critical f(x)=|x+3|-1 is x=-3

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critical f(x)=|x+3|-1

critical points

f (x) = ∣ x + 3 ∣ - 1

x = - 3

Solution steps

∣ x + 3 ∣ - 1

Absolute value functions are piecewise functions

Find the function intervals:

x < - 3, x = - 3, x > - 3

Evaluate the function behavior for each interval

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3

\frac{e ^{x}}{e ^{x} + 2}

e^{4 y - x^{2} - y^{2}}

f (x) = y + x (x^{2} + y^{2})

f (x) = x^{3} + y^{3} - 9 x y

y = \frac{2 x - 1}{x - 1}