What is the asymptotes of f(x)=(3+2x^2)/(2x^2-5) ?

The asymptotes of f(x)=(3+2x^2)/(2x^2-5) is Vertical: x=-sqrt(5/2),x=sqrt(5/2),Horizontal: y=1

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asymptotes of f(x)=(3+2x^2)/(2x^2-5)

asymptotes

f (x) = \frac{3 + 2 x ^{2}}{2 x ^{2} - 5}

Vertical : x = - \frac{5}{2}, x = \frac{5}{2}, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{3 + 2 x ^{2}}{2 x ^{2} - 5} : x = - \frac{5}{2}, x = \frac{5}{2}

Horizontal Asymptotes of

\frac{3 + 2 x ^{2}}{2 x ^{2} - 5} : y = 1

Slant Asymptotes of

\frac{3 + 2 x ^{2}}{2 x ^{2} - 5} :

None

Vertical : x = - \frac{5}{2}, x = \frac{5}{2}, Horizontal : y = 1

\frac{x ^{2}}{( x ^{2} + 1 )}

y = x 4 - x

y = \frac{x ^{2} - 1}{x ^{4} + 1}

x^{4} - 4 x

f (x) = \frac{2 x ^{2} + 2 x - 12}{x ^{2} + x}

What is the asymptotes of f(x)=(3+2x^2)/(2x^2-5) ?
The asymptotes of f(x)=(3+2x^2)/(2x^2-5) is Vertical: x=-sqrt(5/2),x=sqrt(5/2),Horizontal: y=1