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Beliebt Geometry >

leitkurve x=2y^2

Lösung

leitkurve

x = 2 y^{2}

Lösung

x = - \frac{1}{8}

Schritte zur Lösung

Rewrite

x = 2 y^{2}

in the standard form:

4 \cdot \frac{1}{8} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{8}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{8}

Fasse zusammen

x = - \frac{1}{8}

Graph

Beliebte Beispiele

foki 0=-400/9 x^2+16y^2+400

f oc i 0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

5 x^{2} + 7 y = 3

center 41x^2+16y^2+246x-192y+289=0

ce n t er 41 x^{2} + 16 y^{2} + 246 x - 192 y + 289 = 0

x^2+14x+y^2-6y-23=0

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

x = 2 y - y^{2}