x^2+20y=10

Lösung

x^{2} + 20 y = 10

(h, k) = (0, \frac{1}{2}), p = - 5

Schritte zur Lösung

x^{2} + 20 y = 10

Rewrite

x^{2} + 20 y = 10

in the standard form:

4 (- 5) (y - \frac{1}{2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{1}{2}), p = - 5

y^{2} = x - 9

0 = (y - 1)^{2} - 16 (x + y)

x = - \frac{1}{2} (y - 4)^{2} + \frac{1}{2}

x^{2} - y = 9

3 x^{2} - 9 x - 5 y - 2 = 0