de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

2x^2+2y^2+4x-12y+11=0

Lösung

2 x^{2} + 2 y^{2} + 4 x - 12 y + 11 = 0

Lösung

(a, b) = (- 1, 3), r = \frac{3}{2}

Schritte zur Lösung

2 x^{2} + 2 y^{2} + 4 x - 12 y + 11 = 0

Rewrite

2 x^{2} + 2 y^{2} + 4 x - 12 y + 11 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = \frac{3}{2}

Graph

Beliebte Beispiele

a^{2} + b^{2} = 2009

x^{2} + (y - 4)^{2} = 9

x^2+y^2-3x+4y+4=0

x^{2} + y^{2} - 3 x + 4 y + 4 = 0

x^2+y^2-10x+10y=0

x^{2} + y^{2} - 10 x + 10 y = 0

x^{2} + (y - 1)^{2} = 25