x^2+y^2=400

解答

x^{2} + y^{2} = 400

(a, b) = (0, 0), r = 20

求解步骤

x^{2} + y^{2} = 400

将

x^{2} + y^{2} = 400

改写为圆标准方程

(x - 0)^{2} + (y - 0)^{2} = 2 0^{2}

因此圆的性质是:

(a, b) = (0, 0), r = 20

(x + 1)^{2} + (y + 2)^{2} = 8

x^{2} + y^{2} + 12 x + 18 y + 92 = 0

x^{2} + y^{2} - 2 y = 3

x^{2} + y^{2} - 10 x - 10 y + 46 = 0

x^{2} + y^{2} - 16 y - 36 = 0