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Beliebt Geometry >

x^2+y^2-x>= 0

Lösung

x^{2} + y^{2} - x \geq 0

Lösung

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

Schritte zur Lösung

x^{2} + y^{2} - x \geq 0

Rewrite

x^{2} + y^{2} - x \geq 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

Graph

Beliebte Beispiele

x^{2} + y^{2} = 196

2x^2+2y^2-16x+4y+20=0

2 x^{2} + 2 y^{2} - 16 x + 4 y + 20 = 0

(x+1/2)^2+(y-2)^2=3

(x + \frac{1}{2})^{2} + (y - 2)^{2} = 3

x^2+y^2+2x-8y-19=0

x^{2} + y^{2} + 2 x - 8 y - 19 = 0

(x+2)^2+(y+2)^2=9

(x + 2)^{2} + (y + 2)^{2} = 9