9x^2+9y^2-42x+94y+65=0

解

9 x^{2} + 9 y^{2} - 42 x + 94 y + 65 = 0

(a, b) = (\frac{7}{3}, - \frac{47}{9}), r = \frac{2065}{9}

解答ステップ

9 x^{2} + 9 y^{2} - 42 x + 94 y + 65 = 0

9 x^{2} + 9 y^{2} - 42 x + 94 y + 65 = 0

を標準的な円のequationの形式で書き換える

(x - \frac{7}{3})^{2} + (y - (- \frac{47}{9}))^{2} = (\frac{2065}{9})^{2}

ゆえに円の特性は:

(a, b) = (\frac{7}{3}, - \frac{47}{9}), r = \frac{2065}{9}