x^2+2y=0

Lösung

x^{2} + 2 y = 0

(h, k) = (0, 0), p = - \frac{1}{2}

Schritte zur Lösung

x^{2} + 2 y = 0

Rewrite

x^{2} + 2 y = 0

in the standard form:

4 (- \frac{1}{2}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{2}

y^{2} - 12 x - 2 y - 25 = 0

x^{2} - 4 y = 0

x = y^{2} - y

4 x^{2} - 8 x - 3 y - 2 = 0

x^{2} - y = 3