x^2+y^2-12/11 x-84/11 y-640/11 =0

Lösung

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

(a, b) = (\frac{6}{11}, \frac{42}{11}), r = \frac{2 2210}{11}

Schritte zur Lösung

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

Rewrite

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

in the form of the standard circle equation

(x - \frac{6}{11})^{2} + (y - \frac{42}{11})^{2} = (\frac{2 2210}{11})^{2}

Therefore the circle properties are:

(a, b) = (\frac{6}{11}, \frac{42}{11}), r = \frac{2 2210}{11}

x^{2} + 8 x + y^{2} + 2 y + 13 = 0

x^{2} + y^{2} - 6 x + 4 y - 2 = 0

(x + \frac{5}{7})^{2} + (y + \frac{2}{7})^{2} = 8

x^{2} + y^{2} - 2 x + 4 y - 5 = 0

(x - 17)^{2} + (y - 5)^{2} = 144