x^2+y^2-5x+4y=16

解答

x^{2} + y^{2} - 5 x + 4 y = 16

(a, b) = (\frac{5}{2}, - 2), r = \frac{105}{2}

求解步骤

x^{2} + y^{2} - 5 x + 4 y = 16

将

x^{2} + y^{2} - 5 x + 4 y = 16

改写为圆标准方程

(x - \frac{5}{2})^{2} + (y - (- 2))^{2} = (\frac{105}{2})^{2}

因此圆的性质是:

(a, b) = (\frac{5}{2}, - 2), r = \frac{105}{2}

x^{2} + 2 x + 1 + y^{2} + 4 y + 4 - 36 = 0

(x - 1)^{2} + (y + 11)^{2} = 100

9 x^{(2)} + 9 y^{(2)} - 6 x + 24 y = 19

(x - 1)^{2} + (y + 3)^{2} = 1

(x + 3)^{2} + (y + 2)^{2} = 25