x=y^2+3y

Lösung

x = y^{2} + 3 y

(h, k) = (- \frac{9}{4}, - \frac{3}{2}), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} + 3 y

Rewrite

x = y^{2} + 3 y

in the standard form

4 \cdot \frac{1}{4} (x - (- \frac{9}{4})) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{4}, - \frac{3}{2}), p = \frac{1}{4}

(y - (1))^{2} = 2 (x - 1)

y^{2} = 7 x

\frac{1}{3} y - x^{2} + 2 x = - 5

x^{2} + 6 x - 8 y + 1 = 0

2 y^{2} = x