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Beliebt Geometry >

x^2+y^2+8x+12y=0

Lösung

x^{2} + y^{2} + 8 x + 12 y = 0

Lösung

(a, b) = (- 4, - 6), r = 213

Schritte zur Lösung

x^{2} + y^{2} + 8 x + 12 y = 0

Rewrite

x^{2} + y^{2} + 8 x + 12 y = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 6))^{2} = (213)^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 6), r = 213

Graph

Beliebte Beispiele

(x-2)^2+(y+2)^2=25

(x - 2)^{2} + (y + 2)^{2} = 25

(x+1)^2+(y-2/3)^2=sqrt(281/3)^2

(x + 1)^{2} + (y - \frac{2}{3})^{2} = \frac{281}{3}^{2}

x^2+y^2+8y-128=0

x^{2} + y^{2} + 8 y - 128 = 0

2x^2+2y^2+8x-12y-6=0

2 x^{2} + 2 y^{2} + 8 x - 12 y - 6 = 0

(x-6)^2+(y-9)^2=49

(x - 6)^{2} + (y - 9)^{2} = 49