x= 1/2 at^2

Lösung

x = \frac{1}{2} a t^{2}

(h, k) = (0, 0), p = \frac{1}{2 a}

Schritte zur Lösung

x = \frac{1}{2} a t^{2}

Rewrite

x = \frac{1}{2} a t^{2}

in the standard form:

4 \cdot \frac{1}{2 a} (x - 0) = (t - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{2 a}

(x - 3)^{2} = 12 (y - 1)

y^{2} + y + x - 20 = 0

x^{2} - 18 x + 36 y - 207 = 0

x = (y - 2)^{2}

2 x = 3 y^{2}