(x+3)^2=16(y-9)

Lösung

(x + 3)^{2} = 16 (y - 9)

(h, k) = (- 3, 9), p = 4

Schritte zur Lösung

(x + 3)^{2} = 16 (y - 9)

Rewrite

(x + 3)^{2} = 16 (y - 9)

in the standard form:

4 \cdot 4 (y - 9) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 9), p = 4

y^{2} - 2 y - x + 1 = 0

y^{2} - 6 y = 8 x - 1

4 x^{2} + 8 y + 64 = 0

y \leq 3 x^{2} - 6 x + 1

16 y^{2} - x \geq 0