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Beliebt Geometry >

center 2x^2+2y^2-17x=0

Lösung

center

2 x^{2} + 2 y^{2} - 17 x = 0

Lösung

(\frac{17}{4}, 0)

Schritte zur Lösung

2 x^{2} + 2 y^{2} - 17 x = 0

Rewrite

2 x^{2} + 2 y^{2} - 17 x = 0

in the form of the standard circle equation

(x - \frac{17}{4})^{2} + (y - 0)^{2} = (\frac{17}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{17}{4}, 0), r = \frac{17}{4}

And the center is:

(\frac{17}{4}, 0)

Graph

Beliebte Beispiele

center (x-2)^2+(y+3)^2=36

ce n t er (x - 2)^{2} + (y + 3)^{2} = 36

center x^2+y^2-4x-2y-4=0

ce n t er x^{2} + y^{2} - 4 x - 2 y - 4 = 0

center 4x^2+12x+4y^2+16y-11=0

ce n t er 4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

center 100x^2+100y^2-100x+400y+409=0

ce n t er 100 x^{2} + 100 y^{2} - 100 x + 400 y + 409 = 0

center (x^2)/9+(y^2)/9 =1

ce n t er \frac{x ^{2}}{9} + \frac{y ^{2}}{9} = 1