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Beliebt Geometry >

center x^2+y^2-8x-4y-16=0

Lösung

center

x^{2} + y^{2} - 8 x - 4 y - 16 = 0

Lösung

(4, 2)

Schritte zur Lösung

x^{2} + y^{2} - 8 x - 4 y - 16 = 0

Rewrite

x^{2} + y^{2} - 8 x - 4 y - 16 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 2)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (4, 2), r = 6

And the center is:

(4, 2)

Graph

Beliebte Beispiele

center (x+4)^2+(y-2)^2=121

ce n t er (x + 4)^{2} + (y - 2)^{2} = 121

center (x-1)^2+(y-2)^2=1

ce n t er (x - 1)^{2} + (y - 2)^{2} = 1

center (x+11)^2+(y+5)^2=4

ce n t er (x + 11)^{2} + (y + 5)^{2} = 4

center 2x^2+2y^2+8x-12y-72=0

ce n t er 2 x^{2} + 2 y^{2} + 8 x - 12 y - 72 = 0

center (x+3)^2+(y-1)^2=5

ce n t er (x + 3)^{2} + (y - 1)^{2} = 5