-f(x)=4x^2+4x-2

Lösung

- f (x) = 4 x^{2} + 4 x - 2

(h, k) = (- \frac{1}{2}, 3), p = - \frac{1}{16}

Schritte zur Lösung

- y = 4 x^{2} + 4 x - 2

Rewrite

- y = 4 x^{2} + 4 x - 2

in the standard form

4 (- \frac{1}{16}) (y - 3) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, 3), p = - \frac{1}{16}

(y - (- 1))^{2} = 2 (x - 1)

y > - x^{2} - 3 x + 1

5 x + 3 y^{2} = 0

(y - 3)^{2} = 16 (x + 5)

y^{2} + 4 x + 1 = 0