x^2+4x+4y=4

Lösung

x^{2} + 4 x + 4 y = 4

(h, k) = (- 2, 2), p = - 1

Schritte zur Lösung

x^{2} + 4 x + 4 y = 4

Rewrite

x^{2} + 4 x + 4 y = 4

in the standard form

4 (- 1) (y - 2) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 2), p = - 1

(x - 0)^{2} = 8 (y - 1)

x^{2} - 4 x + 2 k (x) = 0

x^{2} - 14 x - 12 y + 29 = 0

2 y^{2} - 3 y + 3 x = 0

x = - y^{2} + 2 y