((x+1.23)^2)/(1.59^2)+(y^2)/(1.01^2)=1

Lösung

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

(h, k) = (- 1.23, 0), a = 1.59, b = 1.01

Schritte zur Lösung

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

Rewrite

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1.23 ) ) ^{2}}{1.5 9 ^{2}} + \frac{( y - 0 ) ^{2}}{1.0 1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1.23, 0), a = 1.59, b = 1.01

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1.23, 0), a = 1.59, b = 1.01

\frac{x ^{2}}{12} + \frac{y ^{2}}{9} = 1

5 x^{2} + 6 y^{2} - 30 x - 24 y + 39 = 0

\frac{( x ^{2} )}{( 16 )} + \frac{( y ^{2} )}{( 12 )} = 1

\frac{( x - 3 ) ^{2}}{16} + \frac{( y - 7 ) ^{2}}{64} = 1

2 x^{2} + 3 y^{2} + 4 x = 19