x^2-2x-4y+13=0

Lösung

x^{2} - 2 x - 4 y + 13 = 0

(h, k) = (1, 3), p = 1

Schritte zur Lösung

x^{2} - 2 x - 4 y + 13 = 0

Rewrite

x^{2} - 2 x - 4 y + 13 = 0

in the standard form

4 \cdot 1 \cdot (y - 3) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 3), p = 1

(y + 3)^{2} = 4 (x + 1)

(y - 1)^{2} = 2 (x + 1)

y^{2} + x - 4 = 0

x^{2} = 64 (y - 5)

x^{2} - 20 y = 0