((x+2)^2)/9+((y-4)^2)/(16)=1

Lösung

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{16} = 1

(h, k) = (- 2, 4), a = 3, b = 4

Schritte zur Lösung

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} + \frac{( y - 4 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 4), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 4), b = 4, a = 3

25 x^{2} + 64 y^{2} = 1600

\frac{x ^{2}}{25} + \frac{y ^{2}}{76} = 1

2 y^{2} = 4 - 5 x^{2}

\frac{( x - 4 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{15} + \frac{y ^{2}}{64} = 1