((x+2)^2)/4+((y-2)^2)/(36)=1

Lösung

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{36} = 1

(h, k) = (- 2, 2), a = 2, b = 6

Schritte zur Lösung

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} + \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 2), a = 2, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 2), b = 6, a = 2

9 x^{2} + 25 y^{2} + 18 x + 50 y - 191 = 0

(\frac{x ^{2}}{64}) + (\frac{y ^{2}}{36}) = 1

X^{2} + 2 \cdot Y^{2} - 2 \cdot X - 4 \cdot Y - 8 = 0

4 x^{2} + 16 y^{2} + 16 x + 160 y + 352 = 0

y^{2} = \frac{1 - 4 x ^{2}}{5}