f(x)(b-2)=3x^2-2

Lösung

f (x) (b - 2) = 3 x^{2} - 2

(h, k) = (0, - \frac{2}{b - 2}), p = \frac{b - 2}{12}

Schritte zur Lösung

y (b - 2) = 3 x^{2} - 2

Rewrite

y (b - 2) = 3 x^{2} - 2

in the standard form:

4 \cdot \frac{b - 2}{12} (y - (- \frac{2}{b - 2})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{2}{b - 2}), p = \frac{b - 2}{12}

x = 7 y^{2} + 5

y - x^{2} - 6 x - 4 = 0

(x - 4)^{2} = 8 (y - 3)

x^{2} - y \geq 0

x^{2} + 4 x - 6 y + 22 = 0