de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

center 16x^2+4y^2-32x+24y-12=0

Lösung

center

16 x^{2} + 4 y^{2} - 32 x + 24 y - 12 = 0

Lösung

(1, - 3)

Schritte zur Lösung

16 x^{2} + 4 y^{2} - 32 x + 24 y - 12 = 0

Rewrite

16 x^{2} + 4 y^{2} - 32 x + 24 y - 12 = 0

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 3), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 3), b = 4, a = 2

And the center is:

(1, - 3)

Graph

Beliebte Beispiele

center x^2+y^2-10y=0

ce n t er x^{2} + y^{2} - 10 y = 0

center (x^2)/9+(y^2)/4 =1

ce n t er \frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

center 6x^2+9y^2-18y-45=0

ce n t er 6 x^{2} + 9 y^{2} - 18 y - 45 = 0

center ((x-3)^2)/(25)+((y+2)^2)/(81)=1

ce n t er \frac{( x - 3 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{81} = 1

center 25x^2+4y^2-50x+16y-59=0

ce n t er 25 x^{2} + 4 y^{2} - 50 x + 16 y - 59 = 0