exzentrizität (x^2)/4+y^2=1

Lösung

exzentrizität

\frac{x ^{2}}{4} + y^{2} = 1

\frac{3}{2}

Dezimale

0.86602 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{4} + y^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 1

= \frac{2 ^{2} - 1 ^{2}}{2}

\frac{2 ^{2} - 1 ^{2}}{2} = \frac{3}{2}

= \frac{3}{2}

ecce n t r i c i t y \frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

ecce n t r i c i t y \frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{1 3 ^{2}} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

ecce n t r i c i t y 18 y^{2} + 24 y + 12 x^{2} - 12 x = 1

ecce n t r i c i t y 9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0