exzentrizität (x^2)/9+(y^2)/(49)=1

Lösung

exzentrizität

\frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1

\frac{2 10}{7}

Dezimale

0.90350 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 3

= \frac{7 ^{2} - 3 ^{2}}{7}

\frac{7 ^{2} - 3 ^{2}}{7} = \frac{2 10}{7}

= \frac{2 10}{7}

ecce n t r i c i t y \frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + (y - 4)^{2} = 1

ecce n t r i c i t y 9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

ecce n t r i c i t y \frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1