achse (x^2}{16}+\frac{y^2)/4 =1

Lösung

achse

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

semi - major axis a = 4, semi - minor axis b = 2

Schritte zur Lösung

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 2

a x i s 4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

a x i s x^{2} + 4 y^{2} = 16

a x i s \frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

a x i s 16 x^{2} + 25 y^{2} + 32 x - 384 = 0

a x i s \frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1