x^2-10x-38y=-25-38

Lösung

x^{2} - 10 x - 38 y = - 25 - 38

(h, k) = (5, 1), p = \frac{19}{2}

Schritte zur Lösung

x^{2} - 10 x - 38 y = - 25 - 38

Rewrite

x^{2} - 10 x - 38 y = - 25 - 38

in the standard form

4 \cdot \frac{19}{2} (y - 1) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, 1), p = \frac{19}{2}

y - 2 = (x - 3)^{2}

3 y^{2} + 48 x = 0

x^{2} = 26 y

(x - 3)^{2} = 12 (y - 4)

y^{2} \leq x